-4=8x^2-18x+5

Solution for -4=8x^2-18x+5 equation:

-4=8x^2-18x+5

We move all terms to the left:

-4-(8x^2-18x+5)=0

We get rid of parentheses

-8x^2+18x-5-4=0

We add all the numbers together, and all the variables

-8x^2+18x-9=0

a = -8; b = 18; c = -9;
Δ = b2-4ac
Δ = 182-4·(-8)·(-9)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*-8}=\frac{-24}{-16}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*-8}=\frac{-12}{-16}
=3/4
$